How to sequentially SORT numbers that also have a letter attached?

Try:
declare @.t table
(
x varchar (5) primary key
, y as case when patindex ('%[a-z]', x) = 0 then ''
else right (x, len (x) - patindex ('%[a-z]', x) + 1) end
, z as case when patindex ('%[a-z]', x) = 0 then cast (x as int)
else cast (left (x, patindex ('%[a-z]', x) - 1) as int) end
)
insert @.t values ('1')
insert @.t values ('1a')
insert @.t values ('1b')
insert @.t values ('1c')
insert @.t values ('2')
insert @.t values ('2a')
insert @.t values ('2b')
insert @.t values ('2c')
insert @.t values ('3')
insert @.t values ('3a')
insert @.t values ('3b')
insert @.t values ('3c')
insert @.t values ('11a')
insert @.t values ('21c')
select x from @.t
order by z, y
Tom
----
Thomas A. Moreau, BSc, PhD, MCSE, MCDBA
SQL Server MVP
Toronto, ON Canada
.
"ALI" <kismet110@.yahoo.co.uk> wrote in message
news:1150111751.001833.272460@.f14g2000cwb.googlegroups.com...
Hi
I'm hoping this will be straightforward for you guys to point me in the
right direction.
Friend of mine emailed me asking the following:
We have a table with a house plot number on it, which is varchar(5).
Example values are:
1
1a
1b
1c
2
2a
2b
2c
3
3a
3b
3c
11a
21c
When we sort these they come out as follows:
1
1a
1b
1c
11a
2
2a
2b
2c
21c
3
3a
3b
3c
Is there an easy way to get them to sort as per the first example? I.e.
1 first, then 1a, 1b, 1c followed by 2, 2a etc and not 11a?
I thought it'd be simple but not so! Would appreciate your advice on
the simplest way of achieving this please.Hi
I'm hoping this will be straightforward for you guys to point me in the
right direction.
Friend of mine emailed me asking the following:
We have a table with a house plot number on it, which is varchar(5).
Example values are:
1
1a
1b
1c
2
2a
2b
2c
3
3a
3b
3c
11a
21c
When we sort these they come out as follows:
1
1a
1b
1c
11a
2
2a
2b
2c
21c
3
3a
3b
3c
Is there an easy way to get them to sort as per the first example? I.e.
1 first, then 1a, 1b, 1c followed by 2, 2a etc and not 11a?
I thought it'd be simple but not so! Would appreciate your advice on
the simplest way of achieving this please.|||Try:
declare @.t table
(
x varchar (5) primary key
, y as case when patindex ('%[a-z]', x) = 0 then ''
else right (x, len (x) - patindex ('%[a-z]', x) + 1) end
, z as case when patindex ('%[a-z]', x) = 0 then cast (x as int)
else cast (left (x, patindex ('%[a-z]', x) - 1) as int) end
)
insert @.t values ('1')
insert @.t values ('1a')
insert @.t values ('1b')
insert @.t values ('1c')
insert @.t values ('2')
insert @.t values ('2a')
insert @.t values ('2b')
insert @.t values ('2c')
insert @.t values ('3')
insert @.t values ('3a')
insert @.t values ('3b')
insert @.t values ('3c')
insert @.t values ('11a')
insert @.t values ('21c')
select x from @.t
order by z, y
Tom
----
Thomas A. Moreau, BSc, PhD, MCSE, MCDBA
SQL Server MVP
Toronto, ON Canada
.
"ALI" <kismet110@.yahoo.co.uk> wrote in message
news:1150111751.001833.272460@.f14g2000cwb.googlegroups.com...
Hi
I'm hoping this will be straightforward for you guys to point me in the
right direction.
Friend of mine emailed me asking the following:
We have a table with a house plot number on it, which is varchar(5).
Example values are:
1
1a
1b
1c
2
2a
2b
2c
3
3a
3b
3c
11a
21c
When we sort these they come out as follows:
1
1a
1b
1c
11a
2
2a
2b
2c
21c
3
3a
3b
3c
Is there an easy way to get them to sort as per the first example? I.e.
1 first, then 1a, 1b, 1c followed by 2, 2a etc and not 11a?
I thought it'd be simple but not so! Would appreciate your advice on
the simplest way of achieving this please.|||Thanks for your help Tom, hopefully this will get them what they want,
I don't feel totally stupid now too for thinking it would be _really_
simple!
Tom Moreau wrote:
> Try:
> declare @.t table
> (
> x varchar (5) primary key
> , y as case when patindex ('%[a-z]', x) = 0 then ''
> else right (x, len (x) - patindex ('%[a-z]', x) + 1) end
> , z as case when patindex ('%[a-z]', x) = 0 then cast (x as int)
> else cast (left (x, patindex ('%[a-z]', x) - 1) as int) end
> )
> insert @.t values ('1')
> insert @.t values ('1a')
> insert @.t values ('1b')
> insert @.t values ('1c')
> insert @.t values ('2')
> insert @.t values ('2a')
> insert @.t values ('2b')
> insert @.t values ('2c')
> insert @.t values ('3')
> insert @.t values ('3a')
> insert @.t values ('3b')
> insert @.t values ('3c')
> insert @.t values ('11a')
> insert @.t values ('21c')
> select x from @.t
> order by z, y
> --
> Tom
> ----
> Thomas A. Moreau, BSc, PhD, MCSE, MCDBA
> SQL Server MVP
> Toronto, ON Canada
> .
> "ALI" <kismet110@.yahoo.co.uk> wrote in message
> news:1150111751.001833.272460@.f14g2000cwb.googlegroups.com...
> Hi
> I'm hoping this will be straightforward for you guys to point me in the
> right direction.
> Friend of mine emailed me asking the following:
> We have a table with a house plot number on it, which is varchar(5).
> Example values are:
> 1
> 1a
> 1b
> 1c
> 2
> 2a
> 2b
> 2c
> 3
> 3a
> 3b
> 3c
> 11a
> 21c
> When we sort these they come out as follows:
> 1
> 1a
> 1b
> 1c
> 11a
> 2
> 2a
> 2b
> 2c
> 21c
> 3
> 3a
> 3b
> 3c
> Is there an easy way to get them to sort as per the first example? I.e.
> 1 first, then 1a, 1b, 1c followed by 2, 2a etc and not 11a?
> I thought it'd be simple but not so! Would appreciate your advice on
> the simplest way of achieving this please.|||Thanks for your help Tom, hopefully this will get them what they want,
I don't feel totally stupid now too for thinking it would be _really_
simple!
Tom Moreau wrote:
> Try:
> declare @.t table
> (
> x varchar (5) primary key
> , y as case when patindex ('%[a-z]', x) = 0 then ''
> else right (x, len (x) - patindex ('%[a-z]', x) + 1) end
> , z as case when patindex ('%[a-z]', x) = 0 then cast (x as int)
> else cast (left (x, patindex ('%[a-z]', x) - 1) as int) end
> )
> insert @.t values ('1')
> insert @.t values ('1a')
> insert @.t values ('1b')
> insert @.t values ('1c')
> insert @.t values ('2')
> insert @.t values ('2a')
> insert @.t values ('2b')
> insert @.t values ('2c')
> insert @.t values ('3')
> insert @.t values ('3a')
> insert @.t values ('3b')
> insert @.t values ('3c')
> insert @.t values ('11a')
> insert @.t values ('21c')
> select x from @.t
> order by z, y
> --
> Tom
> ----
> Thomas A. Moreau, BSc, PhD, MCSE, MCDBA
> SQL Server MVP
> Toronto, ON Canada
> .
> "ALI" <kismet110@.yahoo.co.uk> wrote in message
> news:1150111751.001833.272460@.f14g2000cwb.googlegroups.com...
> Hi
> I'm hoping this will be straightforward for you guys to point me in the
> right direction.
> Friend of mine emailed me asking the following:
> We have a table with a house plot number on it, which is varchar(5).
> Example values are:
> 1
> 1a
> 1b
> 1c
> 2
> 2a
> 2b
> 2c
> 3
> 3a
> 3b
> 3c
> 11a
> 21c
> When we sort these they come out as follows:
> 1
> 1a
> 1b
> 1c
> 11a
> 2
> 2a
> 2b
> 2c
> 21c
> 3
> 3a
> 3b
> 3c
> Is there an easy way to get them to sort as per the first example? I.e.
> 1 first, then 1a, 1b, 1c followed by 2, 2a etc and not 11a?
> I thought it'd be simple but not so! Would appreciate your advice on
> the simplest way of achieving this please.